Suppose you have the following data with two factors and three responses, and you want to find the factor setting that produces responses in a certain region:
data a; input x1 x2 y1 y2 y3; datalines; -1 -1 1.8 1.940 3.6398 -1 1 2.6 1.843 4.9123 1 -1 5.4 1.063 6.0128 1 1 0.7 1.639 2.3629 0 0 8.5 0.134 9.0910 0 0 3.0 0.545 3.7349 0 0 9.8 0.453 10.4412 0 0 4.1 1.117 5.0042 0 0 4.8 1.690 6.6245 0 0 5.9 1.165 6.9420 0 0 7.3 1.013 8.7442 0 0 9.3 1.179 10.2762 1.4142 0 3.9 0.945 5.0245 -1.4142 0 1.7 0.333 2.4041 0 1.4142 3.0 1.869 5.2695 0 -1.4142 5.7 0.099 5.4346 ;
You want to find the values of x1
and x2
that maximize y1
subject to y2
<2 and y3
<y2
+y1
. The exact answer is not easy to obtain analytically, but you can obtain a practically feasible solution by checking conditions
across a grid of values in the range of interest. First, append a grid of factor values to the observed data, with missing
values for the responses:
data b; set a end=eof; output; if eof then do; y1=.; y2=.; y3=.; do x1=-2 to 2 by .1; do x2=-2 to 2 by .1; output; end; end; end; run;
Next, use PROC RSREG to fit a response surface model to the data and to compute predicted values for both the observed data
and the grid, putting the predicted values in a data set c
:
proc rsreg data=b out=c; model y1 y2 y3=x1 x2 / predict; run;
Finally, find the subset of predicted values that satisfy the constraints, sort by the unconstrained variable, and display the top five predictions:
data d; set c; if y2<2; if y3<y2+y1; proc sort data=d; by descending y1; run; data d; set d; if (_n_ <= 5); proc print; run;
The results are displayed in Figure 87.5. They indicate that optimal values of the factors are around 0.3 for x1
and around –0.5 for x2
.
If you are also interested in simultaneously optimizing y1
and y2
, you can specify the following statements to make a visual comparison of the two response surfaces by overlaying their contour
plots:
ods graphics on; proc rsreg data=a plots=surface(overlaypairs); model y1 y2=x1 x2; run; ods graphics off;
Figure 87.6 shows that you have to make some compromises in any attempt to maximize both y1
and y2
; however, you might be able to maximize y1
while minimizing y2
.